45.0g of water is at 20.0^ºC.The water releases 2000.J of heat energy.What is the new temperature of the water?

Question

Quizplus · Accepted Answer

The heat lost by the water is used to raise its temperature. The specific heat capacity of water is 4.18 J/g°C. So, the temperature change is:ΔT = Q / (m * c) = 2000 J / (45.0 g * 4.18 J/g°C) = 10.6 °CThe new temperature is:T_new = T_initial + ΔT = 20.0 °C + 10.6 °C = 30.6 °C

450g of Water Is at 20