A sample of water releases 4.50 x 10³ J of heat energy and its temperature drops from 80.0^ºC to 68.0^ºC.What is the mass of the water?

Question

Quizplus · Accepted Answer

The mass of the water can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat energy released (4.50 x 10^13 J), $m$ is the mass of the water, $c$ is the specific heat capacity of water (4.186 J/g°C), and $\Delta T$ is the change in temperature (80.0°C - 68.0°C = 12.0°C). Rearranging the formula to solve for $m$, we get $m = \frac{q}{c\Delta T}$. Plugging in the values, $m = \frac{4.50 \times 10^{13}}{4.186 \times 12}$, which calculates to approximately 89.6g.

A Sample of Water Releases 4