How many kiloJoules of heat energy are required to raise the temperature of 400.0g of water from 18.0^ºC to 25.0^ºC?

Question

Quizplus · Accepted Answer

To calculate the heat energy required, use the formula $q = mc\Delta T$, where $q$ is the heat energy, $m$ is the mass of the water, $c$ is the specific heat capacity of water (4.18 J/g°C), and $\Delta T$ is the change in temperature. For 400.0g of water heating from 18.0°C to 25.0°C, $\Delta T = 25.0°C - 18.0°C = 7.0°C$. Thus, $q = 400.0g \times 4.18 J/g°C \times 7.0°C = 11676 J$, which is approximately 11.676 kJ, rounding to 12 kJ.

How Many KiloJoules of Heat Energy Are Required to Raise