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Calculate the Number of Moles of Excess Reactant That Will

Question 17

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Calculate the number of moles of excess reactant that will be left-over when 0.350 g of HCN react with 0.500 g of O2: 4HCN + 5O2 Calculate the number of moles of excess reactant that will be left-over when 0.350 g of HCN react with 0.500 g of O<sub>2</sub>: 4HCN + 5O<sub>2</sub> 2N<sub>2</sub> + 4CO<sub>2</sub> + 2H<sub>2</sub>O A) 0.150 moles B) 3.24 10 <sup> </sup> <sup>3</sup> moles C) 4.50 10 <sup> </sup> <sup>4</sup> moles D) 5.62 10 <sup> </sup> <sup>4</sup> moles 2N2 + 4CO2 + 2H2O


A) 0.150 moles
B) 3.24 Calculate the number of moles of excess reactant that will be left-over when 0.350 g of HCN react with 0.500 g of O<sub>2</sub>: 4HCN + 5O<sub>2</sub> 2N<sub>2</sub> + 4CO<sub>2</sub> + 2H<sub>2</sub>O A) 0.150 moles B) 3.24 10 <sup> </sup> <sup>3</sup> moles C) 4.50 10 <sup> </sup> <sup>4</sup> moles D) 5.62 10 <sup> </sup> <sup>4</sup> moles 10
Calculate the number of moles of excess reactant that will be left-over when 0.350 g of HCN react with 0.500 g of O<sub>2</sub>: 4HCN + 5O<sub>2</sub> 2N<sub>2</sub> + 4CO<sub>2</sub> + 2H<sub>2</sub>O A) 0.150 moles B) 3.24 10 <sup> </sup> <sup>3</sup> moles C) 4.50 10 <sup> </sup> <sup>4</sup> moles D) 5.62 10 <sup> </sup> <sup>4</sup> moles
3 moles
C) 4.50 Calculate the number of moles of excess reactant that will be left-over when 0.350 g of HCN react with 0.500 g of O<sub>2</sub>: 4HCN + 5O<sub>2</sub> 2N<sub>2</sub> + 4CO<sub>2</sub> + 2H<sub>2</sub>O A) 0.150 moles B) 3.24 10 <sup> </sup> <sup>3</sup> moles C) 4.50 10 <sup> </sup> <sup>4</sup> moles D) 5.62 10 <sup> </sup> <sup>4</sup> moles 10
Calculate the number of moles of excess reactant that will be left-over when 0.350 g of HCN react with 0.500 g of O<sub>2</sub>: 4HCN + 5O<sub>2</sub> 2N<sub>2</sub> + 4CO<sub>2</sub> + 2H<sub>2</sub>O A) 0.150 moles B) 3.24 10 <sup> </sup> <sup>3</sup> moles C) 4.50 10 <sup> </sup> <sup>4</sup> moles D) 5.62 10 <sup> </sup> <sup>4</sup> moles
4 moles
D) 5.62 Calculate the number of moles of excess reactant that will be left-over when 0.350 g of HCN react with 0.500 g of O<sub>2</sub>: 4HCN + 5O<sub>2</sub> 2N<sub>2</sub> + 4CO<sub>2</sub> + 2H<sub>2</sub>O A) 0.150 moles B) 3.24 10 <sup> </sup> <sup>3</sup> moles C) 4.50 10 <sup> </sup> <sup>4</sup> moles D) 5.62 10 <sup> </sup> <sup>4</sup> moles 10
Calculate the number of moles of excess reactant that will be left-over when 0.350 g of HCN react with 0.500 g of O<sub>2</sub>: 4HCN + 5O<sub>2</sub> 2N<sub>2</sub> + 4CO<sub>2</sub> + 2H<sub>2</sub>O A) 0.150 moles B) 3.24 10 <sup> </sup> <sup>3</sup> moles C) 4.50 10 <sup> </sup> <sup>4</sup> moles D) 5.62 10 <sup> </sup> <sup>4</sup> moles
4 moles

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