What mass of H₂O is produced when 12.0g of HCl react completely in the following equation?
6HCl + Fe₂O₃ $\rarr$ 2FeCl₃ + 3H₂O

Question

What mass of H₂O is produced when 12.0g of HCl react completely in the following equation? 6HCl + Fe₂O₃ $\rarr$2FeCl₃ + 3H₂O

Quizplus · Accepted Answer

First, correct the chemical equation: $6HCl + Fe_2S_3 \rightarrow 2FeCl_3 + 3H_2O$. To find the mass of $H_2O$ produced, start by calculating the molar mass of $HCl$ (about 36.46 g/mol) and $H_2O$ (about 18.02 g/mol). Given 12.0g of $HCl$, divide by its molar mass to find moles of $HCl$, then use the stoichiometry of the reaction (6 moles of $HCl$ produce 3 moles of $H_2O$) to find moles of $H_2O$ produced. Finally, convert moles of $H_2O$ back to grams. The calculation shows that approximately 2.97g of $H_2O$ is produced.

What Mass of H2O Is Produced When 12 →\rarr→ 2FeCl3 + 3H2O A)2

What Mass of H₂O Is Produced When 12 $\rarr$ 2FeCl₃ + 3H₂O
A)2