Which is the limiting reactant when 3.00 moles of calcium are reacted with 8.00 moles of water in the following equation? Ca + 2H₂O $\rarr$Ca(OH)₂ + H₂

Question

Quizplus · Accepted Answer

To determine the limiting reactant, we need to calculate the amount of product that would be formed if all of the reactants reacted completely.

Using the balanced equation: Ca + 2H2O → Ca(OH)2 + H2

If 3.00 moles of Ca reacts, it will produce 3.00 moles of Ca(OH)2.

If 8.00 moles of H2O reacts, it will produce 16.00 moles of Ca(OH)2.

Since Ca produces less Ca(OH)2 than H2O, it is the limiting reactant. Therefore, choice A is the best choice.

Which Is the Limiting Reactant When 3 →\rarr→ Ca(OH)2 + H2 A)Ca B)H2O C)Ca(OH)2 D)H2

Which Is the Limiting Reactant When 3 $\rarr$ Ca(OH)₂ + H₂
A)Ca
B)H₂O
C)Ca(OH)₂
D)H₂