Which substance is in excess when 1.50 moles of aluminum bromide are reacted with 2.50 moles of barium hydroxide in the following equation? 2AlBr₃ + 3Ba(OH)₂ $\rarr$ 3BaBr₂ + 2Al(OH)₃

Question

Quizplus · Accepted Answer

In the balanced chemical equation, the stoichiometric ratio between aluminum bromide and barium hydroxide is 2:3. So, if 1.50 moles of aluminum bromide are used, then the theoretical amount of barium hydroxide required would be (1.50 moles AlBr3) x (3 moles Ba(OH)2 / 2 moles AlBr3) = 2.25 moles Ba(OH)2. Since only 2.50 moles of Ba(OH)2 are given, it is in excess. Therefore, the excess substance is Ba(OH)2 and the answer is C.

Which Substance Is in Excess When 1 →\rarr→ 3BaBr2 + 2Al(OH)3 A)BaBr2 B)Al(OH)3 C)Ba(OH)2 D)AlBr3

Which Substance Is in Excess When 1 $\rarr$ 3BaBr₂ + 2Al(OH)₃
A)BaBr₂
B)Al(OH)₃
C)Ba(OH)₂
D)AlBr₃