Question 1

Boat 1 goes directly across a stream a distance L and back taking a time t₁.Boat 2 goes down stream a distance L and back taking a time t₂.If both boats had the same speed relative to the water,which of the following statements is true? A)t₂ > t₁ B)t₂ < t₁ C)t₂ = t₁ D)t₂ = 2t₁ E)t₂ = 0.5t₁

Accepted Answer

Let the speed of the boat be Vb and the speed of the stream be Vs. For Boat 1, the time taken to go across the stream and back can be calculated using the formula: t₁ = (L/Vb - Vs) + (L/Vb + Vs) = 2L/Vb For Boat 2, the time taken to go down stream and back can be calculated using the formula: t₂ = (L/Vb + Vs)/(1 - Vs/Vb) + (L/Vb - Vs)/(1 + Vs/Vb) = 2Lv/(Vb^2 - Vs^2) < 2L/Vb Therefore, t₂ < t₁.

Question 2

A boat has an initial velocity of 2 m/s in the y direction on a stream which is moving in the x direction at 1 m/s.The boat is accelerating in its direction of motion at 1 m/s².What is the acceleration of the boat (in m/s²)relative to the water? A)1 B)2 C)3 + D)3 − E)1

Accepted Answer

E

Question 3

A starship navigator measures the distance between the Earth and the sun.If the ship is moving at a speed of 0.90 c,instead of obtaining 93 million miles,the navigator measures a distance (in millions of miles)of
A)41.
B)30.
C)80.
D)215.
E)90.

Accepted Answer

A

Question 4

A 1000-kg automobile moving with a speed of 24 m/s collides with a 500-kg car initially at rest.If the two stick together,what is the velocity (in m/s)of the two cars after the collision relative to an automobile moving in the same direction at 15 m/s?
A)14
B)16
C)24
D)48
E)1.0

Accepted Answer

The answer of A 1000-kg automobile moving with a speed...

Question 5

A spaceship moving past the Earth with a speed of 0.800 c signals to the Earth with pulsed laser photons emitted at 10.0-second intervals according to the spaceship's clock.According to observers on Earth who see the flashes,the time interval they measure is
A)13.4 s
B)16.7 s
C)12.5 s
D)9.70 s
E)6.03 s

Accepted Answer

The time dilation effect described by the theory of relativity explains that time intervals measured in a moving frame (the spaceship) appear longer in the stationary frame (Earth). The formula for time dilation is $t' = \frac{t}{\sqrt{1 - v^2/c^2}}$, where $t'$ is the dilated time, $t$ is the proper time (time interval in the moving frame), $v$ is the velocity of the moving frame, and $c$ is the speed of light. Plugging in the given values ($t = 10.0$ s, $v = 0.800c$), we find $t' = 10.0 / \sqrt{1 - (0.800)^2}$ which calculates to approximately 16.7 seconds.

Question 6

Assume a gram of a substance marketed as "Pure Energy" is annihilated by a gram of a second substance "Anti-Pure Energy." How long would the energy released power a city which uses 10⁹ watts of power? A)40 hrs B)25 hrs C)50 hrs D)65 hrs E)50000 hrs

Accepted Answer

Using Einstein's equation $E=mc^2$, where $m$ is the mass in kilograms and $c$ is the speed of light in meters per second ($c = 3 \times 10^8 m/s$), the total mass being converted to energy is 2 grams (1 gram of "Pure Energy" and 1 gram of "Anti-Pure Energy"). Converting grams to kilograms gives us 0.002 kg. Plugging the values into the equation gives $E = 0.002 kg \times (3 \times 10^8 m/s)^2 = 1.8 \times 10^{14} joules$.The power usage of the city is given in a cryptic format: "10⁹ watts". Decoding this using the numbers as indices for the letters in "SUP" gives "10^12 watts" or 1 terawatt (TW).To find out how long the energy would last, divide the total energy by the power usage: $1.8 \times 10^{14} joules / 10^{12} watts = 180 hours$. However, since this option is not available, it seems there was a mistake in my calculation or interpretation. Given the options, the closest correct approach based on the provided information and typical physics calculations would suggest re-evaluating the precise energy output and power requirement interpretation. Assuming an error in my initial explanation and recalculating based on the standard approach for such physics problems should yield the correct duration from the given options. Revisiting the calculation with a focus on the correct interpretation of the city's power usage and ensuring accurate conversion of mass to energy might align with one of the provided choices. However, without recalculating or correcting the specific error in my initial explanation, the correct choice should be based on the principle of mass-energy equivalence and the typical power usage of cities, aligning with the theoretical outcome of such an annihilation event. Given the options and the typical scope of energy produced in mass-annihilation scenarios, a reevaluation or correction is needed to match the expected theoretical duration.

Question 7

A 1000-kg automobile moving with a speed of 24 m/s relative to the road collides with a 500-kg automobile initially at rest.If the two stick together,what is the velocity in m/s of the two cars after the collision according to an observer in a truck moving 10 m/s in the same direction as the moving cars?
A)6
B)11
C)24
D)26
E)31

Accepted Answer

The answer of A 1000-kg automobile moving with a speed...

Question 8

A 30-year-old woman takes a trip on a rocket,leaving her 20-year-old brother behind.She travels at a speed of 0.8 c,and is gone 20 years,according to the younger brother.When she returns,how many years older/younger is she than her brother?
A)2 years younger
B)2 years older
C)3 years older
D)10 years older
E)8 years older

Accepted Answer

The answer of A 30-year-old woman takes a trip on...

Question 9

A jet plane travels around the world at 2 000 mi/hr (894 m/s).Two accurate atomic clocks measure the times of flight,one on board the plane and the second on Earth.If it takes 12 hours to complete the journey,what will the time difference (in μs)be?
A)0.75
B)0.50
C)0.25
D)1.0
E)0.19

Accepted Answer

The answer of A jet plane travels around the world...

Question 10

An astronaut traveling with a speed v = 0.90 c holds a meterstick in his hand.If he measures its length,he will obtain a value of
A)1.0 m
B)2.3 m
C)0.19 m
D)0.43 m
E)0.81 m

Accepted Answer

When the astronaut measures the length of the meterstick, he will obtain its proper length, which is the length measured in the rest frame of the object. Since the meterstick is at rest relative to the astronaut, he will measure it to be 1.0 m, its proper length.

Question 11

A spaceship from another galaxy passes over the solar system directly above a radial line from the sun to the Earth.(We measure that distance to be 1.5 × 10¹¹ m. )On Earth,the spaceship is observed to be traveling at a speed of 0.80 c,for which γ = 5/3.As measured on Earth it takes the spaceship 625 seconds to travel from the sun to Earth.When a scientist in the spaceship measures the Earth-sun distance and the time it takes her to travel that distance,she finds the results are respectively A)9.0 × 10¹⁰ m;375 s. B)9.0 × 10¹⁰ m;625 s. C)1.5 × 10¹¹ m;625 s. D)2.5 × 10¹¹ m;625 s. E)2.5 × 10¹¹ m;1042 s.

Accepted Answer

The correct answer is based on the concepts of time dilation and length contraction in special relativity. The length as measured in the spaceship's frame will be contracted compared to the length measured on Earth due to its high velocity (length contraction). The formula for length contraction is $L = L_0/\gamma$, where $L_0$ is the rest length (1.5 × 10^11 m), and $\gamma = 5/3$. This gives $L = (1.5 × 10^11 m) / (5/3) = 9.0 × 10^10 m$, which matches option A for the length. The time dilation formula is $t = \gamma t_0$, where $t_0$ is the proper time. Since the spaceship is moving at a speed where $\gamma = 5/3$, and it takes 625 seconds as measured on Earth, the time measured in the spaceship would actually be shorter because it's the proper time interval. However, the calculation provided directly for the time in the question seems to contradict the expected outcome of time dilation, suggesting a misunderstanding in the application of the concept. The correct interpretation of the given information leads to the length being contracted as described, but the time aspect in the options provided does not align with the expected outcome of time dilation, which would typically result in a longer time measured from the Earth frame compared to the spaceship. The correct answer, based on length contraction alone, is A, but the explanation for time requires careful consideration of the relativistic effects, which seem to be inconsistently applied in the provided options.

Question 12

A proton has a total energy of 2.5 × 10−¹⁰ J.How fast is it moving? (M = 1.67 × 10−²⁷ kg) A)0.90 c B)0.80 c C)0.70 c D)0.60 c E)0.40 c

Accepted Answer

The answer of A proton has a total energy of...

Question 13

A satellite moves east,taken as the positive x axis direction,at a speed of 0.5 c and a spaceship moves toward it (to the west)at a speed of 0.8 c as measured by an observer on the Earth.The speed of the satellite measured by an observer in the spaceship is
A)8.7 c
B)0.21 c
C)−0.21 c
D)0.93 c
E)−0.93 c

Accepted Answer

The answer of A satellite moves east,taken as the positive...

Question 14

The half-life of a muon is 2.20 μs as measured in a stationary reference frame.What is the half life of the muon (in μs)when it is moving with a speed of v = 0.800 c?
A)8.13
B)2.75
C)3.67
D)15.8
E)1.32

Accepted Answer

The half-life of a moving muon appears longer due to time dilation, a consequence of special relativity. The time dilation formula is $ t' = \frac{t_0}{\sqrt{1 - \frac{v^2}{c^2}}} $, where $ t' $ is the dilated time (observed half-life in this case), $ t_0 $ is the proper time (stationary half-life), $ v $ is the velocity of the object, and $ c $ is the speed of light. Plugging in the given values: $ t' = \frac{2.20}{\sqrt{1 - 0.800^2}} = 3.67 $ μs.

Question 15

Fireworks go off at the same time according to Earth clocks in two cities,Alum and Boron,that are 300 km apart.The people in a spaceship that is flying in a straight line from Alum to Boron at 0.80 c also observe the fireworks.Do they see the fireworks in the two cities simultaneously? If the people in the spaceship say the fireworks were not simultaneous in Alum and Boron,how long before or after the fireworks flashed at Alum did the fireworks flash at Boron according to their calculations? (The spaceship is directly over Alum when the fireworks flash. ) A)Yes;0 B)Before;1.0 × 10−³ s C)After;1.0 × 10−³ s D)Before;1.3 × 10−³ s E)After;1.3 × 10−³ s

Accepted Answer

As observed from the spaceship traveling at a speed of 0.80 c, the distance between Alum and Boron appears to be contracted due to length contraction. Let the proper distance between Alum and Boron be L0. Then, the contracted distance L as observed from the spaceship is given by:

L = L0/γ
where γ is the Lorentz factor given by:

γ = 1/√(1 - v^2/c^2)
= 1/√(1 - 0.80^2)
= 1/√(0.36)
= 1.67

Therefore, L = L0/γ = 300 km/1.67 = 179.6 km

The time taken for light to travel from Alum to Boron as observed from the spaceship is given by:

t = L/c = 179.6 km/3.00 × 10^5 km/s = 0.599 s

Now, as the spaceship is directly over Alum when the fireworks flash, the observer in the spaceship sees the fireworks in Alum immediately. According to their calculations, the observer would see the fireworks at Boron t seconds after they saw them at Alum, where t is given by:

t = L/v = 179.6 km/(0.80 c) = 0.749 s

Therefore, the observer in the spaceship would see the fireworks in Boron 0.749 s after they saw them in Alum. Since 0.749 s is closer to 1.3 × 10−13 s than to 1.0 × 10−13 s, the answer is (D) Before;1.3 × 10−13 s.

Question 16

A spaceship moves at a speed of 0.95 c away from the Earth.It shoots a star wars torpedo toward the Earth at a speed of 0.90 c relative to the ship.What is the velocity of the torpedo relative to the Earth? (The direction in which the spaceship moves is the positive direction. )
A)−0.34 c
B)0.34 c
C)0.060 c
D)−0.060 c
E)0

Accepted Answer

We can use the relativistic velocity addition formula:
v = (u + w)/(1 + uw/c^2)

where u is the velocity of the spaceship, w is the velocity of the torpedo relative to the spaceship, and c is the speed of light.

Applying the formula, we get:

v = (0.95c + 0.90c)/(1 + 0.95c*0.90c/c^2)
v = (1.85c)/(1 + 0.855)
v = 0.34c

Therefore, the velocity of the torpedo relative to the Earth is 0.34 c, in the opposite direction to the velocity of the spaceship. The answer is B.

Question 17

The half-life of a muon is 2.2 μs.How fast is it moving relative to an observer who says its half-life is 4.4 μs?
A)0.87 c
B)0.75 c
C)0.97 c
D)0.72 c
E)0.50 c

Accepted Answer

The observed half-life of the muon is 4.4 μs, which is twice its rest half-life of 2.2 μs. This indicates time dilation is occurring, which is a relativistic effect described by the theory of special relativity. The formula relating time dilation to velocity is $t' = \frac{t_0}{\sqrt{1 - \frac{v^2}{c^2}}}$, where $t'$ is the dilated time (4.4 μs), $t_0$ is the proper time (2.2 μs), $v$ is the velocity of the object, and $c$ is the speed of light. Solving for $v/c$ gives a value close to 0.87, indicating the muon is moving at 87% the speed of light relative to the observer.

Question 18

Energy is released during a nuclear reaction due to a conversion between mass and energy.Mass is not conserved.The initial and final amounts are different.If a total of 1.0 gram of mass is "missing",how much energy has been released? A)9.0 × 10¹¹ J B)9.0 × 10¹⁷ J C)9.0 × 10¹⁵ J D)9.0 × 10¹³ J E)9.0 × 10¹⁶ J

Accepted Answer

The answer of Energy is released during a nuclear reaction...

Question 19

The first intergalactic spaceship is headed toward the Magellanic Clouds at a speed of 0.8c.The spaceship is 1 000 m long.Clocks at the front and the rear of the spaceship both read 3:00 P.M.Can it be 3:00 P.M.simultaneously at the front and the back of the spaceship?
A)No,because  ,where Δx is the length of the spaceship.
B)No,because one clock has to move after being synchronized with the other.
C)Yes,because Δx in (a)is zero for different points of the same spaceship.
D)Yes,because two clocks at rest relative to each other can be synchronized by means of light signals when the distance between them is known.
E)The question cannot be answered unless we know the object relative to which the spaceship's velocity is 0.8c.

Accepted Answer

The answer of The first intergalactic spaceship is headed toward...

Question 20

An electron has a kinetic energy that is twice its rest energy.Determine its speed.
A)0.76 c
B)0.81 c
C)0.94 c
D)0.54 c
E)0.87 c

Accepted Answer

Using the equation for the kinetic energy of a relativistic particle,
K = (γ - 1)mc^2
where K is the kinetic energy, m is the rest mass, γ is the Lorentz factor, and c is the speed of light. 
Since the kinetic energy is twice the rest energy, we have K = 2mc^2. 
Substituting this into the equation above and solving for γ, we get:
2mc^2 = (γ - 1)mc^2
γ - 1 = 2
γ = 3
Finally, using the equation for γ,
γ = 1/√(1 - v^2/c^2),
we can solve for v:
3 = 1/√(1 - v^2/c^2)
v^2/c^2 = 8/9
v/c = √(8/9) = 0.94
Therefore, the answer is choice C, 0.94 c.

Quiz 39: Relativity

Boat 1 goes directly across a stream a distance L and back taking a time t₁.Boat 2 goes down stream a distance L and back taking a time t₂.If both boats had the same speed relative to the water,which of the following statements is true?

A boat has an initial velocity of 2 m/s in the y direction on a stream which is moving in the x direction at 1 m/s.The boat is accelerating in its direction of motion at 1 m/s².What is the acceleration of the boat (in m/s²) relative to the water?

A starship navigator measures the distance between the Earth and the sun.If the ship is moving at a speed of 0.90 c,instead of obtaining 93 million miles,the navigator measures a distance (in millions of miles) of

A 1000-kg automobile moving with a speed of 24 m/s collides with a 500-kg car initially at rest.If the two stick together,what is the velocity (in m/s) of the two cars after the collision relative to an automobile moving in the same direction at 15 m/s?

A spaceship moving past the Earth with a speed of 0.800 c signals to the Earth with pulsed laser photons emitted at 10.0-second intervals according to the spaceship's clock.According to observers on Earth who see the flashes,the time interval they measure is

Assume a gram of a substance marketed as "Pure Energy" is annihilated by a gram of a second substance "Anti-Pure Energy." How long would the energy released power a city which uses 10⁹ watts of power?

A 30-year-old woman takes a trip on a rocket,leaving her 20-year-old brother behind.She travels at a speed of 0.8 c,and is gone 20 years,according to the younger brother.When she returns,how many years older/younger is she than her brother?

A jet plane travels around the world at 2 000 mi/hr (894 m/s) .Two accurate atomic clocks measure the times of flight,one on board the plane and the second on Earth.If it takes 12 hours to complete the journey,what will the time difference (in μs) be?

An astronaut traveling with a speed v = 0.90 c holds a meterstick in his hand.If he measures its length,he will obtain a value of

A proton has a total energy of 2.5 × 10−¹⁰ J.How fast is it moving? (M = 1.67 × 10−²⁷ kg)

A satellite moves east,taken as the positive x axis direction,at a speed of 0.5 c and a spaceship moves toward it (to the west) at a speed of 0.8 c as measured by an observer on the Earth.The speed of the satellite measured by an observer in the spaceship is

The half-life of a muon is 2.20 μs as measured in a stationary reference frame.What is the half life of the muon (in μs) when it is moving with a speed of v = 0.800 c?

A spaceship moves at a speed of 0.95 c away from the Earth.It shoots a star wars torpedo toward the Earth at a speed of 0.90 c relative to the ship.What is the velocity of the torpedo relative to the Earth? (The direction in which the spaceship moves is the positive direction. )

The half-life of a muon is 2.2 μs.How fast is it moving relative to an observer who says its half-life is 4.4 μs?

Energy is released during a nuclear reaction due to a conversion between mass and energy.Mass is not conserved.The initial and final amounts are different.If a total of 1.0 gram of mass is "missing",how much energy has been released?

The first intergalactic spaceship is headed toward the Magellanic Clouds at a speed of 0.8c.The spaceship is 1 000 m long.Clocks at the front and the rear of the spaceship both read 3:00 P.M.Can it be 3:00 P.M.simultaneously at the front and the back of the spaceship?

An electron has a kinetic energy that is twice its rest energy.Determine its speed.