Upon combustion, about how many grams of water vapor are produced from every 16 grams of methane, CH₄? CH₄ + 2 O₂ → CO₂ + 2 H₂O

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The combustion of methane produces water vapor and carbon dioxide. The balanced chemical equation for the combustion of methane is:CH₄ + 2 O₂ → CO₂ + 2 H₂OFrom the balanced chemical equation, we can see that 1 mole of methane (16 grams) reacts with 2 moles of oxygen to produce 2 moles of water vapor (36 grams). Therefore, upon combustion, about 36 grams of water vapor are produced from every 16 grams of methane.

Upon Combustion, About How Many Grams of Water Vapor Are