A baseball is released at rest from the top of the Washington Monument.It hits the ground after falling for 5.85 s.What was the height from which the ball was dropped? (g = 9.80 m/s² and assume air resistance is negligible) A)1.88 × 10² m B)1.68 × 10² m C)1.38 × 10² m D)3.36 × 10² m

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Quizplus · Accepted Answer

The height from which the ball was dropped can be calculated using the formula for the distance covered under constant acceleration: $d = \frac{1}{2}gt^2$, where $g = 9.80 \, \text{m/s}^2$ and $t = 5.85 \, \text{s}$. Plugging in the values, we get $d = \frac{1}{2} \times 9.80 \times (5.85)^2 = 1.68 \times 10^2 \, \text{m}$.

A Baseball Is Released at Rest from the Top of the Washington