A trapeze artist,with swing,weighs 800 N;he is momentarily held to one side by his partner so that the swing ropes make an angle of 25.0° with the vertical.In such a condition of static equilibrium,what is the horizontal force being applied by the partner?
A)338 N
B)693 N
C)400 N
D)373 N
E)572 N

Question

Quizplus · Accepted Answer

Since the trapeze artist is in static equilibrium, the forces acting on him must balance out. The weight of the trapeze artist is 800 N, which can be split into components:

- Vertical component = 800 N x cos(25.0°) = 729 N 
- Horizontal component = 800 N x sin(25.0°) = 338 N

The partner is holding the trapeze artist horizontally, so the force they are applying must balance out the horizontal component of the weight of the trapeze artist. Therefore, the horizontal force applied by the partner is 338 N.

So, the correct option is D.

A Trapeze Artist,with Swing,weighs 800 N;he Is Momentarily Held to One