Jack pulls a sled across a level field by exerting a force of 120.0 N at an angle of 30.0° with the ground.What are the parallel and perpendicular components,respectively,of this force with respect to the ground?
A)208 N,120 N
B)120 N,208 N
C)104 N,60 N
D)60 N,104 N
E)69 N,208 N

Question

Quizplus · Accepted Answer

The parallel (horizontal) component of the force can be found using $F_{\parallel} = F \cos(\theta)$ and the perpendicular (vertical) component using $F_{\perp} = F \sin(\theta)$, where $F = 120.0 \, \text{N}$ and $\theta = 30.0°$. Thus, $F_{\parallel} = 120.0 \cos(30.0°) = 104 \, \text{N}$ and $F_{\perp} = 120.0 \sin(30.0°) = 60 \, \text{N}$.

Jack Pulls a Sled Across a Level Field by Exerting