A 0.150-m-radius grinding wheel,starting at rest,develops an angular speed of 12.0 rad/s in a time interval of 4.00 s.What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s? A)0.450 m/s² B)7.20 m/s² C)14.4 m/s² D)28.8 m/s²

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Quizplus · Accepted Answer

Centripetal acceleration is given by $ a_c = r \omega^2 $. Here, $ r = 0.100 \, \text{m} $ and $ \omega = 12.0 \, \text{rad/s} $. So, $ a_c = 0.100 \times (12.0)^2 = 14.4 \, \text{m/s}^2 $.

A 0150-M-Radius Grinding Wheel,starting at Rest,develops an Angular Speed of 12