A 0.40-kg mass,attached to the end of a 0.75-m string,is whirled around in a circular horizontal path.If the maximum tension that the string can withstand is 450 N,then what maximum speed can the mass have if the string is not to break?
A)370 m/s
B)22 m/s
C)19 m/s
D)29 m/s

Question

Quizplus · Accepted Answer

The maximum tension in the string is given by:$$T = mv^2/r$$where m is the mass, v is the speed, and r is the radius of the circular path.Solving for v, we get:$$v = sqrt(Tr/m)$$Substituting the given values, we get:$$v = sqrt(450 N * 0.75 m / 0.40 kg) = 29 m/s$$

A 040-Kg Mass,attached to the End of a 0