A 0.30-m-radius automobile tire accelerates from rest at a constant 2.0 rad/s² over a 5.0-s interval.What is the tangential component of acceleration for a point on the outer edge of the tire during the 5.0-s interval? A)33 m/s² B)6.7 m/s² C)0.60 m/s² D)0.30 m/s²

Question

Quizplus · Accepted Answer

The tangential acceleration is given by the formula $ a_t = \alpha \times r $, where $ \alpha = 2.0 \, \text{rad/s}^2 $ and $ r = 0.30 \, \text{m} $. Thus, $ a_t = 2.0 \times 0.30 = 0.60 \, \text{m/s}^2 $.

A 030-M-Radius Automobile Tire Accelerates from Rest at a Constant 2