A proton (+1.6 × 10−¹⁹ C)moves 15.0 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

Question

Quizplus · Accepted Answer

The electrical potential difference (ΔV) can be calculated using the formula ΔV = -E * d, where E is the electric field strength and d is the distance moved along the field. Here, E = 3.0 N/C and d = 15.0 cm = 0.15 m. Thus, ΔV = -(3.0 N/C)(0.15 m) = -0.45 V. The negative sign indicates the direction of potential difference relative to the field direction, but the magnitude of the potential difference is 0.45 V.

A Proton (+1