Question 1

Two equal positive charges are separated by d. Then one of the charges is replaced by a negative charge of the same magnitudeTake the potential at infinity to be zero.In which situation is the potential higher midway between the charges;is this value of potential zero?

Accepted Answer

In the first situation, where both charges are positive, the potential midway between them is positive because electric potential due to a point charge is positive for positive charges and negative for negative charges. Since both charges are positive and equal, their potentials add up, resulting in a positive value. In the second situation, one charge is positive and the other is negative; their potentials at the midpoint cancel each other out, leading to a net potential of zero. Therefore, the potential is higher in the first situation, but it is not zero.

Question 2

A uniform electric field,with a magnitude of 650 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 700 V,what is the potential at x = 1.0 m?

Accepted Answer

C

Question 3

An ion is released from rest and moves due to the force from an electric field from a position in the field having a potential of 14 V to a position having a potential of 8 V.The ion:

Accepted Answer

The ion moves from higher potential (14 V) to lower potential (8 V), which means it is moving in the direction of decreasing potential energy. As negative charges move in the opposite direction to the electric field, the ion must be positively charged to move in the direction of the electric field. Therefore, the correct answer is A) must have a positive charge.

Question 4

A 10-V battery moves 7.0 mC of charge through a circuit running from its positive terminal to its negative terminal.How much energy was delivered to the circuit?

Accepted Answer

The energy delivered to a circuit can be calculated using the equation:

E = QV

Where E is the energy in joules (J), Q is the charge in coulombs (C), and V is the voltage in volts (V).

In this case, we are given that the battery moves 7.0 mC of charge (Q) through a circuit running from its positive terminal to its negative terminal, and that the voltage (V) is 10 V.

Plugging these values into the equation, we get:

E = (7.0 × 10^-3 C) × (10 V) = 0.070 J

Therefore, the answer is C, 0.070 J.

Question 5

If an electron is accelerated from rest through a potential difference of 1 200 V,find its approximate velocity at the end of this process.(e = 1.6 × 10−¹⁹ C;m_e = 9.1 × 10−³¹ kg)

Accepted Answer

The kinetic energy gained by the electron is equal to the potential energy it lost, which is given by qΔV, where q is the charge of the electron and ΔV is the potential difference. Therefore, the kinetic energy gained by the electron is (1.6 × 10^-19 C) x (1200 V) = 1.92 × 10^-16 J. Using the formula for kinetic energy (K = 1/2 mv^2), we can solve for the velocity v:

1/2 mv^2 = 1.92 × 10^-16 J

v^2 = (2 x 1.92 × 10^-16 J) / m

v = sqrt[(2 x 1.92 × 10^-16 J) / m] = 2.08 x 10^7 m/s

Rounding to two significant figures gives a final answer of 2.1 x 10^7 m/s, which is choice C.

Question 6

Four point charges are on the rim of a circle of radius 10 cm.The charges are (in μC)+0.50,+1.5,−1.0,−0.50.If the electrical potential at the circle's center due to the +0.5 charge alone is 4.5 × 10⁴ V,what is the total potential at the center due to the four charges combined?

Accepted Answer

The answer of Four point charges are on the rim...

Question 7

An electron in a cathode ray tube is accelerated through a potential difference of 8.0 kV.What kinetic energy does the electron gain in the process? (e = 1.6 × 10−¹⁹ C)

Accepted Answer

The kinetic energy gained by an electron can be calculated by:
K.E. = qV
where q is the charge of the electron and V is the potential difference.

Substituting the given values, we get:
K.E. = (1.6 × 10^-19 C) × (8.0 × 10^3 V) 
K.E. = 1.28 × 10^-15 J

Therefore, the correct answer is B) 1.3E-15 J.

Question 8

A free electron is in an electric field.With respect to the field,it experiences a force acting:

Accepted Answer

A free electron experiences a force in the direction opposite to the electric field because it has a negative charge, and the direction of the force on a charge in an electric field is given by the charge times the electric field vector.

Question 9

A proton (+1.6 × 10−¹⁹ C)moves 20 cm on a path in the direction of a uniform electric field of strength 2.4 N/C.How much work is done on the proton by the electrical field?

Accepted Answer

The work done on the proton by the electric field is calculated using the formula W = qEd, where q is the charge of the proton (1.6 × 10^-19 C), E is the electric field strength (2.4 N/C), and d is the distance moved (20 cm = 0.2 m). Thus, W = (1.6 × 10^-19 C)(2.4 N/C)(0.2 m) = 7.68 × 10^-20 J, which rounds to 7.7 × 10^-20 J.

Question 10

A 10.00-V battery is connected between two parallel metal plates 4.00 mm apart.What is the magnitude of the electric field between the plates?

Accepted Answer

The electric field (E) between two parallel plates is given by the formula E = V/d, where V is the voltage (10.00 V) and d is the distance between the plates (4.00 mm = 0.004 m). Plugging in the values, E = 10.00 V / 0.004 m = 2500 N/C, which is 2.50 × 10^3 N/C.

Question 11

The quantity of electrical potential,the volt,is dimensionally equivalent to:

Accepted Answer

The volt is defined as the potential difference across a conductor when a current of one ampere dissipates one watt of power. It can also be expressed as the product of electric field (E) and distance (d), hence dimensionally equivalent to electric field times distance.

Question 12

​A proton is released from rest in a uniform electric field.Which statement is correct?

Accepted Answer

Since the proton has a positive charge, it will be attracted towards the negative plate of the electric field. The direction of the electric field is from higher to lower electric potential, thus the proton will move in the same direction as the electric field to regions of lower electric potential.

Question 13

A proton (+1.6 × 10−¹⁹ C)moves 15.0 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

Accepted Answer

The electrical potential difference (ΔV) can be calculated using the formula ΔV = -E * d, where E is the electric field strength and d is the distance moved along the field. Here, E = 3.0 N/C and d = 15.0 cm = 0.15 m. Thus, ΔV = -(3.0 N/C)(0.15 m) = -0.45 V. The negative sign indicates the direction of potential difference relative to the field direction, but the magnitude of the potential difference is 0.45 V.

Question 14

Two particles each have the same mass but particle #1 has four times the charge of particle #2.Particle #1 is accelerated from rest through a potential difference of 10 V and attains speed v.Particle #2 is accelerated from rest also through a potential difference of 10 V.What speed does particle #2 attain?

Accepted Answer

The answer of Two particles each have the same mass...

Question 15

The unit of electrical potential,the volt,is dimensionally equivalent to:

Accepted Answer

The unit of electrical potential, the volt (V), is defined as joules per coulomb (J/C), which represents the potential energy difference (in joules) per unit of charge (in coulombs).

Question 16

A positively charged particle is released from rest in a uniform electric field.Which statement regarding the electron is correct?

Accepted Answer

As the particle moves in the direction of the electric field, it experiences a force that accelerates it. This results in an increase in the particle's kinetic energy. The total energy of the particle (kinetic energy + potential energy) also increases, but the potential energy itself does not change since it is only dependent on the position of the particle in the field. The electric potential at the particle's location does not necessarily increase, as it depends on the strength of the electric field and the distance between the charges creating the field.

Question 17

An electron (charge −1.6 × 10−¹⁹ C)moves on a path perpendicular to the direction of a uniform electric field of strength 2.0 N/C.How much work is done on the electron as it moves 14.0 cm?

Accepted Answer

When an electron moves perpendicular to the direction of a uniform electric field, the electric field does no work on the electron because the work done by the electric field is given by $W = qEd\cos(\theta)$, where $q$ is the charge, $E$ is the electric field strength, $d$ is the distance moved, and $\theta$ is the angle between the direction of the electric field and the direction of motion. Since $\theta = 90^\circ$ for perpendicular motion, $\cos(90^\circ) = 0$, making $W = 0$.

Question 18

In which case does an electric field do positive work on a charged particle?

Accepted Answer

When a negative charge moves opposite to the direction of the electric field, it is moving in the direction of the force exerted by the field, resulting in positive work done on the charge.

Question 19

An electron and a proton are each released from rest in the same uniform electric field.The electron moves a distance d_electron and the proton moves a distance d_proton as each particle's kinetic energy increases by 1.6 eV.How do d_electron and d_proton compare?

Accepted Answer

The work done on both particles is the same (1.6 eV), and since they have the same charge magnitude, they will move the same distance in the electric field.

Question 20

Case 1: An electron is released from rest in a uniform electric field.Case 2: A proton is released from rest in a uniform electric field of the same magnitude as in case 1.How does the electric potential energy of the charge-field system behave in these cases?

Accepted Answer

When a charge is released in an electric field, it moves from a region of higher potential energy to a region of lower potential energy, regardless of whether the charge is positive (proton) or negative (electron). This movement results in a decrease in electric potential energy for both cases.

Quiz 16: Electrical Energy and Capacitance

Two equal positive charges are separated by d. Then one of the charges is replaced by a negative charge of the same magnitudeTake the potential at infinity to be zero.In which situation is the potential higher midway between the charges;is this value of potential zero?

A uniform electric field,with a magnitude of 650 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 700 V,what is the potential at x = 1.0 m?

An ion is released from rest and moves due to the force from an electric field from a position in the field having a potential of 14 V to a position having a potential of 8 V.The ion:

A 10-V battery moves 7.0 mC of charge through a circuit running from its positive terminal to its negative terminal.How much energy was delivered to the circuit?

If an electron is accelerated from rest through a potential difference of 1 200 V,find its approximate velocity at the end of this process.(e = 1.6 × 10−¹⁹ C;m_e = 9.1 × 10−³¹ kg)

Four point charges are on the rim of a circle of radius 10 cm.The charges are (in μC) +0.50,+1.5,−1.0,−0.50.If the electrical potential at the circle's center due to the +0.5 charge alone is 4.5 × 10⁴ V,what is the total potential at the center due to the four charges combined?

An electron in a cathode ray tube is accelerated through a potential difference of 8.0 kV.What kinetic energy does the electron gain in the process? (e = 1.6 × 10−¹⁹ C)

A free electron is in an electric field.With respect to the field,it experiences a force acting:

A proton (+1.6 × 10−¹⁹ C) moves 20 cm on a path in the direction of a uniform electric field of strength 2.4 N/C.How much work is done on the proton by the electrical field?

A 10.00-V battery is connected between two parallel metal plates 4.00 mm apart.What is the magnitude of the electric field between the plates?

The quantity of electrical potential,the volt,is dimensionally equivalent to:

A proton is released from rest in a uniform electric field.Which statement is correct?

A proton (+1.6 × 10−¹⁹ C) moves 15.0 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

The unit of electrical potential,the volt,is dimensionally equivalent to:

A positively charged particle is released from rest in a uniform electric field.Which statement regarding the electron is correct?

An electron (charge −1.6 × 10−¹⁹ C) moves on a path perpendicular to the direction of a uniform electric field of strength 2.0 N/C.How much work is done on the electron as it moves 14.0 cm?

In which case does an electric field do positive work on a charged particle?

An electron and a proton are each released from rest in the same uniform electric field.The electron moves a distance d_electron and the proton moves a distance d_proton as each particle's kinetic energy increases by 1.6 eV.How do d_electron and d_proton compare?

Case 1: An electron is released from rest in a uniform electric field.Case 2: A proton is released from rest in a uniform electric field of the same magnitude as in case 1.How does the electric potential energy of the charge-field system behave in these cases?

Quiz 16: Electrical Energy and Capacitance

Two equal positive charges are separated by d. Then one of the charges is replaced by a negative charge of the same magnitudeTake the potential at infinity to be zero.In which situation is the potential higher midway between the charges;is this value of potential zero?

A uniform electric field,with a magnitude of 650 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 700 V,what is the potential at x = 1.0 m?

An ion is released from rest and moves due to the force from an electric field from a position in the field having a potential of 14 V to a position having a potential of 8 V.The ion:

A 10-V battery moves 7.0 mC of charge through a circuit running from its positive terminal to its negative terminal.How much energy was delivered to the circuit?

If an electron is accelerated from rest through a potential difference of 1 200 V,find its approximate velocity at the end of this process.(e = 1.6 × 10−19 C;me = 9.1 × 10−31 kg)

Four point charges are on the rim of a circle of radius 10 cm.The charges are (in μC) +0.50,+1.5,−1.0,−0.50.If the electrical potential at the circle's center due to the +0.5 charge alone is 4.5 × 104 V,what is the total potential at the center due to the four charges combined?

An electron in a cathode ray tube is accelerated through a potential difference of 8.0 kV.What kinetic energy does the electron gain in the process? (e = 1.6 × 10−19 C)

A free electron is in an electric field.With respect to the field,it experiences a force acting:

A proton (+1.6 × 10−19 C) moves 20 cm on a path in the direction of a uniform electric field of strength 2.4 N/C.How much work is done on the proton by the electrical field?

A 10.00-V battery is connected between two parallel metal plates 4.00 mm apart.What is the magnitude of the electric field between the plates?

The quantity of electrical potential,the volt,is dimensionally equivalent to:

​A proton is released from rest in a uniform electric field.Which statement is correct?

A proton (+1.6 × 10−19 C) moves 15.0 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

The unit of electrical potential,the volt,is dimensionally equivalent to:

A positively charged particle is released from rest in a uniform electric field.Which statement regarding the electron is correct?

An electron (charge −1.6 × 10−19 C) moves on a path perpendicular to the direction of a uniform electric field of strength 2.0 N/C.How much work is done on the electron as it moves 14.0 cm?

In which case does an electric field do positive work on a charged particle?

An electron and a proton are each released from rest in the same uniform electric field.The electron moves a distance delectron and the proton moves a distance dproton as each particle's kinetic energy increases by 1.6 eV.How do delectron and dproton compare?

Case 1: An electron is released from rest in a uniform electric field.Case 2: A proton is released from rest in a uniform electric field of the same magnitude as in case 1.How does the electric potential energy of the charge-field system behave in these cases?

If an electron is accelerated from rest through a potential difference of 1 200 V,find its approximate velocity at the end of this process.(e = 1.6 × 10−¹⁹ C;m_e = 9.1 × 10−³¹ kg)

Four point charges are on the rim of a circle of radius 10 cm.The charges are (in μC) +0.50,+1.5,−1.0,−0.50.If the electrical potential at the circle's center due to the +0.5 charge alone is 4.5 × 10⁴ V,what is the total potential at the center due to the four charges combined?

An electron in a cathode ray tube is accelerated through a potential difference of 8.0 kV.What kinetic energy does the electron gain in the process? (e = 1.6 × 10−¹⁹ C)

A proton (+1.6 × 10−¹⁹ C) moves 20 cm on a path in the direction of a uniform electric field of strength 2.4 N/C.How much work is done on the proton by the electrical field?

A proton is released from rest in a uniform electric field.Which statement is correct?

A proton (+1.6 × 10−¹⁹ C) moves 15.0 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

An electron (charge −1.6 × 10−¹⁹ C) moves on a path perpendicular to the direction of a uniform electric field of strength 2.0 N/C.How much work is done on the electron as it moves 14.0 cm?

An electron and a proton are each released from rest in the same uniform electric field.The electron moves a distance d_electron and the proton moves a distance d_proton as each particle's kinetic energy increases by 1.6 eV.How do d_electron and d_proton compare?