An electron is moving at a speed of 4.8 × 10⁶ m/s at an angle of 30.0° with respect to a uniform magnetic field of 9.2 × 10^-4 T.What is the radius of the resulting helical path? (m_e = 9.11 × 10^-31 kg,q_e = 1.60 × 10^-19 C) A)2.6 cm B)3.8 cm C)5.5 cm D)1.5 cm E)2.9 cm

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The Answer of An electron is moving at a speed of 4.8 × 10⁶ m/s at an angle of 30.0° with respect to a uniform magnetic field of 9.2 × 10^-4 T.What is the radius of the resulting helical path? (m_e = 9.11 × 10^-31 kg,q_e = 1.60 × 10^-19 C) A)2.6 cm B)3.8 cm C)5.5 cm D)1.5 cm E)2.9 cm

An Electron Is Moving at a Speed of 4