A 1.0-m wire segment carrying a current of 0.55 A oriented parallel to a uniform magnetic field of 0.80 T experiences a force of what magnitude?
A)0.44 N
B)0.22 N
C)0.70 N
D)0.35 N
E)0.00 N

Question

Quizplus · Accepted Answer

The force experienced by a current-carrying wire in a magnetic field is given by the equation F = ILB sin(θ), where I is the current, L is the length of the wire, B is the magnetic field strength, and θ is the angle between the wire and the magnetic field. Since the wire is parallel to the magnetic field, θ = 0 degrees, and sin(0) = 0, which means the force experienced by the wire is 0 N.

A 10-M Wire Segment Carrying a Current of 0