The critical angle for total internal reflection for light entering water (n = 1.33)from oil is 61 $\circ$ .What is the index of refraction of the oil?

Question

Quizplus · Accepted Answer

The critical angle for total internal reflection can be found using Snell's law, $n_1 \sin(\theta_c) = n_2 \sin(90^\circ)$, where $n_1$ is the refractive index of the first medium (oil), $n_2$ is the refractive index of the second medium (water = 1.33), and $\theta_c$ is the critical angle (61 degrees). Rearranging for $n_1$, we get $n_1 = n_2 / \sin(\theta_c)$. Substituting the given values, $n_1 = 1.33 / \sin(61^\circ)$, which calculates to approximately 1.52.

The Critical Angle for Total Internal Reflection for Light Entering ∘\circ∘

The Critical Angle for Total Internal Reflection for Light Entering $\circ$