A beam of light enters a liquid solution from air at an angle of 35 $\circ$ with the normal to its surface.The refracted beam makes an angle of 24 $\circ$ to the normal of the liquid.What is the index of refraction for the liquid?

Question

Quizplus · Accepted Answer

The index of refraction can be calculated using Snell's Law, which is $n_1 \sin(\theta_1) = n_2 \sin(\theta_2)$. Given that the light enters from air ($n_1 = 1$) at an angle of 35° ($\theta_1 = 35°$) and refracts at an angle of 24° ($\theta_2 = 24°$) in the liquid, we can solve for $n_2$, the index of refraction of the liquid. Plugging in the values, we get $1 \times \sin(35°) = n_2 \times \sin(24°)$. Solving for $n_2$, we find that it is approximately 1.4.

A Beam of Light Enters a Liquid Solution from Air ∘\circ∘

A Beam of Light Enters a Liquid Solution from Air $\circ$