A radio tuner has a capacitance of 25.0 nF,and an inductance of 3.00 mH.If the power in the circuit is 3.9 W when the signal produces an rms voltage across the antenna of 1.50 mV and it is at the resonance frequency,what is the resistance of the tuner?
A)0.723 $\mu$$\varOmega$
B)1.00 $\mu$$\varOmega$
C)2.11 $\mu$$\varOmega$
D)0.288 $\mu$$\varOmega$
E)0.577 $\mu$$\varOmega$

Question

Quizplus · Accepted Answer

The resistance can be calculated using the formula $ P = \frac{V_{rms}^2}{R} $. Rearranging gives $ R = \frac{V_{rms}^2}{P} $. Substituting the given values, $ R = \frac{(1.50 \times 10^{-3})^2}{3.9} \approx 0.577 \mu\Omega $.

A Radio Tuner Has a Capacitance of 25 μ\muμ Ω\varOmegaΩ B)100 μ\muμ

A Radio Tuner Has a Capacitance of 25 $\mu$ $\varOmega$ B)100 $\mu$