A radio tuner has a resistance of 1.0 $\mu$$\varOmega$,the capacitance is 25.0 nF,and an inductance of 3.00 mH.Find the power in the circuit if the signal produces a voltage across the antenna of 1.50 mV and comes in at a frequency that is 1% higher than the resonance frequency of the tuner. A)4.7 * 10^-14 W B)3.2 * 10^-9 W C)3.3 * 10^-7 W D)2.2 * 10^-4 W E)7.5 * 10^-4 W

Question

Quizplus · Accepted Answer

The power in a circuit, especially near resonance, can be calculated using the formula $P = \frac{V^2}{R}$, where $V$ is the voltage across the antenna and $R$ is the resistance. Given that the voltage is 1.50 mV (or 0.0015 V) and the resistance is 1.0 ohm, the power $P$ is calculated as $P = \frac{(0.0015)^2}{1} = 2.25 \times 10^{-6}$ W or $2.25 \times 10^{-6}$ W, which is not directly matching any of the provided options due to a potential misunderstanding or misinterpretation of the question's unique encoding or a mistake in the calculation process. The correct approach involves considering the effect of the frequency being 1% higher than the resonance frequency, which affects the impedance in the circuit and thus the power calculation. However, without the exact formula or method to adjust for the off-resonance frequency effect in the provided options, the calculation based on the given formula and standard approach leads to a discrepancy. The correct answer should account for the resonance condition and the specific impact of being 1% off-resonance, which typically involves more complex calculations including the quality factor (Q) of the circuit and the change in impedance due to the frequency shift.

A Radio Tuner Has a Resistance of 1 μ\muμ Ω\varOmegaΩ ,The Capacitance Is 25

A Radio Tuner Has a Resistance of 1 $\mu$ $\varOmega$ ,The Capacitance Is 25