A series LRC circuit is driven by an ideal sinusoidal AC voltage generator with a peak emf of 12 V.If L = 30.0 mH,R = 200 ohms,and C = 0.040 mF,what is the average power dissipated in the resistor if the circuit is driven at the resonance frequency?
A)0.016 W
B)0.21 W
C)0.36 W
D)0.72 W
E)770 W

Question

Quizplus · Accepted Answer

At resonance, the impedance of the circuit is purely resistive, so the average power dissipated is given by P_avg = (V_rms^2) / R. The peak voltage is 12 V, so V_rms = 12 / √2. Thus, P_avg = (12/√2)^2 / 200 = 0.36 W.

A Series LRC Circuit Is Driven by an Ideal Sinusoidal