Consider an series LCR circuit,consisting of a 20-micro Farad capacitance,a 10-milli-Henry inductance,and a 23-Ohm resistor.This circuit is fed by a sinusoidally alternating emf with an amplitude of 2.4 V.What is the maximum instantaneous current in the circuit at a frequency f = 50 Hz?
A)0.015 A
B)0.63 A
C)2.4 A
D)39.2 A
E)110 A

Question

Quizplus · Accepted Answer

The maximum instantaneous current in an LCR circuit is given by I_max = V_max / Z, where Z is the impedance. The impedance Z is calculated using Z = sqrt(R^2 + (X_L - X_C)^2), where X_L = 2πfL and X_C = 1/(2πfC). For the given values, Z = sqrt(23^2 + (2π*50*0.01 - 1/(2π*50*20e-6))^2) = 160.5 Ohms. Therefore, I_max = 2.4 / 160.5 = 0.015 A.

Consider an Series LCR Circuit,consisting of a 20-Micro Farad Capacitance,a