A 5-turn square loop (0.150 m along a side,resistance = 2.00 $\varOmega$ )is placed in a magnetic field that makes an angle of 30 $\circ$ with the normal to the plane of the loop.The magnitude of this field varies with time according to B = 2.40t⁴,where t is measured in s and B in T.What is the induced EMF in the coil at t = 1.38 s? A)2.67 V B)2.87 V C)1.45 V D)2.03 V E)2.46 V

Question

Quizplus · Accepted Answer

The induced EMF ($\varepsilon$) in the coil can be calculated using Faraday's law of electromagnetic induction: $\varepsilon = -N \frac{d\Phi}{dt}$, where $\Phi = B \cdot A \cdot \cos(\theta)$. Here, $N = 5$, $A = (0.150)^2$, $\theta = 30^\circ$, and $B = 2.40t^4$. At $t = 1.38$ s, calculate $\frac{dB}{dt}$ and substitute to find $\varepsilon$. The correct answer is approximately 2.46 V.

A 5-Turn Square Loop (0 Ω\varOmegaΩ )Is Placed in a Magnetic Field That Makes an Angle

A 5-Turn Square Loop (0 $\varOmega$ )Is Placed in a Magnetic Field That Makes an Angle