A 10-turn square loop (0.250 m along a side,resistance = 4.00 $\varOmega$)is placed in a magnetic field that makes an angle $\alpha$ with the normal to the plane of the loop.The magnitude of this field varies with time according to B = 2.70t²,where t is measured in s and B in T.The induced current in the coil at t = 1.50 s is 0.750 A. The angle $\alpha$ made by the magnetic field with the plane of the loop is A)30.0 $\circ$ . B)60.0 $\circ$ . C)36.3 $\circ$ . D)53.7 $\circ$ .

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The Answer of A 10-turn square loop (0.250 m along a side,resistance = 4.00 $\varOmega$)is placed in a magnetic field that makes an angle $\alpha$ with the normal to the plane of the loop.The magnitude of this field varies with time according to B = 2.70t²,where t is measured in s and B in T.The induced current in the coil at t = 1.50 s is 0.750 A. The angle $\alpha$ made by the magnetic field with the plane of the loop is A)30.0 $\circ$ . B)60.0 $\circ$ . C)36.3 $\circ$ . D)53.7 $\circ$ .

A 10-Turn Square Loop (0 Ω\varOmegaΩ )Is Placed in a Magnetic Field That Makes an Angle

A 10-Turn Square Loop (0 $\varOmega$ )Is Placed in a Magnetic Field That Makes an Angle