A rectangular (45 cm long by 22 cm wide)circuit loop with resistance 35 $\varOmega$ is held parallel to the xy-plane with one end inside a uniform magnetic field.The magnetic field for x 0 the magnetic field is zero.Initially the left end of the loop is at x = -30 cm and the right end is at x = 15cm.Calculate the magnitude of the force required to move the loop to the right along the positive x-axis at a constant speed of 13 cm/s while the left end of the loop is still in the magnetic field. A)5.8 * 10^-4 N B)3.2 * 10^-4 N C)1.5 * 10^-3 N D)1.6 * 10^-2 N E)2.0 * 10^-2 N

Question

A rectangular (45 cm long by 22 cm wide)circuit loop with resistance 35 $\varOmega$ is held parallel to the xy-plane with one end inside a uniform magnetic field.The magnetic field for x < 0 is 1.8 T along +z axis,and for x > 0 the magnetic field is zero.Initially the left end of the loop is at x = -30 cm and the right end is at x = 15cm.Calculate the magnitude of the force required to move the loop to the right along the positive x-axis at a constant speed of 13 cm/s while the left end of the loop is still in the magnetic field. A)5.8 * 10^-4 N B)3.2 * 10^-4 N C)1.5 * 10^-3 N D)1.6 * 10^-2 N E)2.0 * 10^-2 N

Quizplus · Accepted Answer

The force required is calculated using the formula F = B²L²v/R, where B is the magnetic field strength (1.8 T), L is the length of the loop in the magnetic field (22 cm = 0.22 m), v is the velocity (13 cm/s = 0.13 m/s), and R is the resistance (35 Ω). Substituting these values gives F = (1.8)² * (0.22)² * 0.13 / 35 = 5.8 * 10⁻⁴ N.

A Rectangular (45 Cm Long by 22 Cm Wide)circuit Loop Ω\varOmegaΩ

A Rectangular (45 Cm Long by 22 Cm Wide)circuit Loop $\varOmega$