A 2.7-mH inductor is connected to a current.How much energy is stored in its magnetic field at time t = 3.0 s if the current is ? (Assume two significant digits for each number.)
A)0.0095 J
B)0.041 J
C)0.066 J
D)0.13 J
E)0.30 J

Question

A 2.7-mH inductor is connected to a current.How much energy is stored in its magnetic field at time t = 3.0 s if the current is  ? (Assume two significant digits for each number.)
A)0.0095 J 
B)0.041 J 
C)0.066 J 
D)0.13 J 
E)0.30 J

Quizplus · Accepted Answer

The energy stored in an inductor is given by the formula: 
E = (1/2) * L * I^2, where L is the inductance and I is the current.
Plugging in the given values, we get: 
E = (1/2) * 2.7 mH * (11 A)^2 = 0.066 J 
Therefore, the answer is choice C: 0.066 J.

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