The Hall affect is used to measure the carrier density of a thin sheet of electrons.When a current flows through the length of the electron sheet,which is 1.2-mm long,0.27-mm wide and 12-nm thick,a magnetic field of 0.75 T perpendicular to the sheet produces a potential difference of 0.53 mV across the width of the sheet.If the carrier density in the electron sheet is 8.49 * 10²⁸ m^-3,what current flows through the length of the sheet?

Question

Quizplus · Accepted Answer

The Hall effect is given by:$$V_H = \frac{IB}{ne}$$where:* $V_H$ is the Hall voltage* $I$ is the current* $B$ is the magnetic field* $n$ is the carrier density* $e$ is the elementary chargeWe can rearrange this equation to solve for the current:$$I = \frac{neV_H}{B}$$Plugging in the given values, we get:$$I = \frac{(8.49 	imes 10^{28} 	ext{ m}^{-3})(0.27 	imes 10^{-3} 	ext{ m})(0.53 	imes 10^{-3} 	ext{ V})}{0.75 	ext{ T}} = 0.12 	ext{ A}$$Therefore, the correct answer is A) 0.12 A.

The Hall Affect Is Used to Measure the Carrier Density