An air gap capacitor is charged up to 10 V and then disconnected.If a material is added to the gap between the plates and the voltage drops to 3.33 V,what is the dielectric constant of that material?

Question

Quizplus · Accepted Answer

The dielectric constant ($k$) of a material can be found using the relation between the initial voltage ($V_i$) without the dielectric and the final voltage ($V_f$) with the dielectric, given by $k = \frac{V_i}{V_f}$. Here, $V_i = 10V$ and $V_f = 3.33V$, so $k = \frac{10}{3.33} \approx 3$. This means the dielectric constant of the material is 3.

An Air Gap Capacitor Is Charged Up to 10 V