A point charge of 10 $\mu$C is surrounded by water (dielectric constant = 80).What is the electric field 0.2 m away?

Question

Quizplus · Accepted Answer

The electric field from a point charge is given by:

E = kq/r^2

where k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q is the point charge, and r is the distance from the charge.

In this case, q = 10 μC and r = 0.2 m.

So, E = (9 x 10^9 Nm^2/C^2) x (10 x 10^-6 C) / (0.2 m)^2 = 28 kN/C

The electric field should be radial outward since the point charge is positive. Therefore, the correct answer is A: 28 kN/C, radial outward.

A Point Charge of 10 μ\muμ C Is Surrounded by Water (Dielectric Constant = 80)