Suppose we have two capacitors connected in parallel with a 10 V battery.What is the energy stored in the circuit if the capacitance of one is C₁ = 50 mF and the other is C₂ = 100 mF?

Question

Quizplus · Accepted Answer

The total capacitance in parallel is C = C1 + C2 = 50 mF + 100 mF = 150 mF. The energy stored is given by E = 0.5 * C * V^2 = 0.5 * 150 * 10^-3 * 10^2 = 7.5 J.

Suppose We Have Two Capacitors Connected in Parallel with a 10