What is the capacitance of two parallel plates 0.9 mm apart with an area of 12 cm² if the space between the plates is filled with a material with dielectric constant of 3.7?

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Quizplus · Accepted Answer

The capacitance $ C $ of parallel plates is given by $ C = \frac{\varepsilon_0 \varepsilon_r A}{d} $, where $ \varepsilon_0 $ is the permittivity of free space ($8.85 \times 10^{-12} \, \text{F/m}$), $ \varepsilon_r $ is the dielectric constant, $ A $ is the area in square meters, and $ d $ is the separation in meters. Converting the area to square meters (0.0012 m$^2$) and the distance to meters (0.0009 m), the capacitance is approximately 44 pF.

What Is the Capacitance of Two Parallel Plates 0 μ\muμ F D)37

What Is the Capacitance of Two Parallel Plates 0 $\mu$ F
D)37