Two capacitors C₁ = 2.5 mF and C₂ = 5.0 mF are connected in parallel.If a voltage of V = 120 volts is applied across the capacitors,what is the energy stored in the capacitors?

Question

Quizplus · Accepted Answer

The total capacitance when capacitors are connected in parallel is equal to the sum of individual capacitances, which is 7.5 mF (0.0075 F).

The energy stored in a capacitor is given by the formula: 
E = 1/2 * C * V^2

where E is the energy in joules (J), C is the capacitance in farads (F), and V is the voltage across the capacitor in volts (V).

Plugging in the values, we get: 
E = 1/2 * 0.0075 * (120)^2 
E = 54 J

Therefore, the energy stored in the capacitors is 54 J. Option C is correct.

Two Capacitors C1 = 2

Two Capacitors C₁ = 2