Two capacitors C₁ = 2.5 mF and C₂ = 5.0 mF are connected in series.If a voltage of V = 120 volts is applied across the capacitors,what is the energy stored in capacitor C₂?

Question

Quizplus · Accepted Answer

The energy stored in a capacitor is given by the equation E = 1/2 CV^2. In this case, the capacitors are connected in series, so the total capacitance is C = C1 + C2 = 2.5 mF + 5.0 mF = 7.5 mF. The voltage across the capacitors is V = 120 volts. Therefore, the energy stored in capacitor C2 is:E2 = 1/2 C2 V^2 = 1/2 (5.0 mF) (120 volts)^2 = 36 J

Two Capacitors C1 = 2

Two Capacitors C₁ = 2