A 0.2-mF capacitor is charged with 4 $\mu$C positive on one plate and 4 $\mu$C negative on the other.What is the voltage (V)on the capacitor?

Question

Quizplus · Accepted Answer

We can use the formula V = Q/C, where V is the voltage, Q is the charge on the capacitor, and C is the capacitance.

In this case, the charge on the capacitor is the difference between the positive and negative charges:

Q = 4 μC - 4 μC = 0 μC

Plugging this into the formula gives:

V = Q/C = 0 μC / 0.2 mF = 0.020 V

Therefore, the answer is (C) 0.020.

A 02-MF Capacitor Is Charged with 4 μ\muμ C Positive on One Plate and 4