In the opposite corners of a square there are two identical ions.Each has a charge of -e.The length of one side of he square is L.What is the magnitude of the net electric field caused by the two negative ions at both of the empty corners of the square?

Question

Quizplus · Accepted Answer

The electric field due to a single ion of charge -e at a distance r from it is given by: E = ke(-e)/r^2 From symmetry, we can see that the electric field components along the diagonal of the square will cancel out, and the field components along the sides of the square will add up. Therefore, the magnitude of the net electric field at both of the empty corners of the square is given by: E = 2E1 = 2ke(-e)/L^2 E = ke/((L^2)/2) E = ke/(LSqrt(2)) E = 11ea821f_c689_fc08_bbd8_5b75584f8383_TB1516_11_TB1516_11_TB1516_11 / (L²) Therefore, the answer is C.

In the Opposite Corners of a Square There Are Two