A 4.00 * 10^-9 C point charge is placed at the origin.Where on the x-axis is the electric field produced by the point charge 157 N/C?

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The electric field of a point charge is given by:$$E = k\frac{q}{r^2}$$where k is Coulomb's constant, q is the charge, and r is the distance from the charge.In this case, we have:$$q = 4.00 * 10^{-9} C$$$$E = 157 N/C$$We want to find the distance r from the charge where the electric field is 157 N/C. Substituting these values into the equation above, we get:$$157 N/C = (9.0 * 10^9 Nm^2/C^2)\frac{4.00 * 10^{-9} C}{r^2}$$Solving for r, we get:$$r = 0.22 m = 22 cm$$Therefore, the electric field produced by the point charge is 157 N/C at a distance of 22 cm from the charge on the x-axis.

A 400 * 10-9 C Point Charge Is Placed at the the Origin.Where

A 400 * 10^-9 C Point Charge Is Placed at the the Origin.Where