A Thin Glass Rod Is Bent into a Semicircle of Radius

A thin glass rod is bent into a semicircle of radius R.A charge + Q is uniformly distributed along the upper half,and a charge -Q is uniformly distributed along the lower half,as shown in the figure.If Q = 10 nC and R = 10 cm,find the magnitude and direction of the electric field E (in component form) at point P,the center of the semicircle.

A) 3.61 * 10⁴ N/C in + y direction
B) 3.61 * 10⁴ N/C in -y direction
C) 1.15 * 10⁴ N/C in + x direction
D) 1.15 * 10⁴ N/C in -y direction