The electrons in a particle beam each have a kinetic energy of 1.6 * 10^-16 J.The magnitude of the electric field that would stop the electrons in a distance of 1 m is

Question

Quizplus · Accepted Answer

The kinetic energy of an electron equals to the work done by the electric field in bringing it from rest to the given speed. Therefore, we can use the work-energy theorem to find the electric field:

K = q * V = W = F * d

where K is the kinetic energy of the electron, q is the electron charge, V is the potential difference across the plates of length d that stop the electron, and F is the electric force on the electron.

Rearranging the equation, we get:

F = K / d * q

Substituting the given values, we get:

F = (1.6 x 10^-16 J) / (1 m) * (1.6 x 10^-19 C) = 1000 N/C

Therefore, the magnitude of the electric field that would stop the electrons in a distance of 1 m is 1000 N/C, which corresponds to choice B.

The Electrons in a Particle Beam Each Have a Kinetic