A Carnot engine uses reservoirs at temperatures of 27.0 $\circ$ C and 327 $\circ$ C.In one cycle,it uses 600 J of heat from the high temperature reservoir.How much work does it do in one cycle?

Question

Quizplus · Accepted Answer

The efficiency of a Carnot engine is given by $ \eta = 1 - \frac{T_C}{T_H} $, where $ T_C $ and $ T_H $ are the absolute temperatures of the cold and hot reservoirs, respectively. Converting the given temperatures to Kelvin: $ T_C = 27 + 273 = 300 $ K and $ T_H = 327 + 273 = 600 $ K. The efficiency is $ 1 - \frac{300}{600} = 0.5 $. The work done is the product of efficiency and heat absorbed: $ 0.5 \times 600 $ J = 300 J.

A Carnot Engine Uses Reservoirs at Temperatures of 27 ∘\circ∘ C and 327

A Carnot Engine Uses Reservoirs at Temperatures of 27 $\circ$ C and 327