If 5.0 J of heat are extracted from the cold reservoir of a Carnot refrigerator operated between 20 $\circ$ C and 0 $\circ$ C,how much heat is expelled into the hot reservoir?

Question

Quizplus · Accepted Answer

The efficiency of a Carnot refrigerator is given by (Th - Tc)/Th, where Th is the temperature of the hot reservoir and Tc is the temperature of the cold reservoir. Using this formula, we can find that the temperature of the hot reservoir is 60C. Since the heat extracted from the cold reservoir is equal to the heat expelled into the hot reservoir, we can calculate that 5.37 J of heat will be expelled into the hot reservoir using the formula Qc/Th = Qh/Th. Therefore, the correct answer is C.

If 50 J of Heat Are Extracted from the Cold Reservoir