One end of a metal rod is in contact with a reservoir at a 400 K and the other end in contact with a reservoir at 100 K.The rod and reservoirs make up a closed system.If 5500 J are conducted from one end to the other uniformly (no change in temperature along the rod)what is the change in entropy of the 400 K reservoir?

Question

Quizplus · Accepted Answer

The change in entropy (ΔS) of the 400 K reservoir is calculated using the formula ΔS = -Q/T, where Q is the heat transferred and T is the temperature. Here, ΔS = -5500 J / 400 K = -13.75 J/K, which rounds to -13.8 J/K.

One End of a Metal Rod Is in Contact with a Reservoir