An 8.2-kg block of copper at 80 $\circ$ C is dropped into a container with 0.62 L of water at 10 $\circ$ C.How much energy in the form of heat is absorbed by the water as the copper and water reach thermal equilibrium?

Question

Quizplus · Accepted Answer

The correct answer is A because the heat absorbed by the water is equal to the heat lost by the copper, which can be calculated using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

An 82-Kg Block of Copper at 80 ∘\circ∘ C Is Dropped into a Container with 0

An 82-Kg Block of Copper at 80^$\circ$C Is Dropped into a Container with 0