A block of aluminum with a mass of 2.6 kg is at 13 $\circ$ C and comes in contact with a hot block of copper with a mass of 10.2 kg at 93 $\circ$ C.What is the final temperature? (c_aluminum = 0.22 kcal/kg $\circ$ C;c_copper = 0.093 kcal/kg $\circ$ C)

Question

Quizplus · Accepted Answer

To solve the problem, we need to use the formula:
(mcΔT)copper + (mcΔT)aluminum = 0
where m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. The subscripts "copper" and "aluminum" refer to the two materials.
Plugging in the given values, we get:
(10.2 kg)(0.093 kcal/kg°C)(Tf - 93°C) + (2.6 kg)(0.22 kcal/kg°C)(Tf - 13°C) = 0
Simplifying and solving for Tf, we get:
Tf = 63°C
Therefore, the final temperature is 63°C, which corresponds to answer choice D.

A Block of Aluminum with a Mass of 2 ∘\circ∘ C and Comes in Contact with a Hot Block of Is

A Block of Aluminum with a Mass of 2 $\circ$ C and Comes in Contact with a Hot Block of Is