541 J of work is required to slide a 20-kg ice block up a frictionless slope.The incline of the slope with respect to horizontal is 9.71 $\circ$ .What is the length of the slope?

Question

Quizplus · Accepted Answer

The work done by gravity on the ice block is mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the slope. Using trigonometry, we can find h to be:

h = d*sin(θ)

where d is the length of the slope and θ is the angle of inclination. Therefore, we have:

mgh = 541 J
(20 kg)*(9.81 m/s^2)*d*sin(9.71°) = 541 J
d = 16 m

Therefore, the length of the slope is 16 meters. The correct answer is C.

541 J of Work Is Required to Slide a 20-Kg ∘\circ∘

541 J of Work Is Required to Slide a 20-Kg $\circ$