A force is applied to a 100-kg go-cart to accelerate it from 10.0 m/s to 20.0 m/s over a 7.00 s time frame.If the acceleration is assumed to be constant over the time frame,what is the magnitude of the force applied?
A)50.0 N
B)123 N
C)143 N
D)150 N

Question

Quizplus · Accepted Answer

First, calculate the acceleration using the formula $a = \frac{\Delta v}{\Delta t}$, where $\Delta v = 20.0 \, \text{m/s} - 10.0 \, \text{m/s} = 10.0 \, \text{m/s}$ and $\Delta t = 7.00 \, \text{s}$. This gives $a = \frac{10.0 \, \text{m/s}}{7.00 \, \text{s}} = 1.43 \, \text{m/s}^2$. Then, use Newton's second law, $F = ma$, with $m = 100 \, \text{kg}$ and $a = 1.43 \, \text{m/s}^2$, to find $F = 100 \, \text{kg} \times 1.43 \, \text{m/s}^2 = 143 \, \text{N}$.

A Force Is Applied to a 100-Kg Go-Cart to Accelerate