A 2-kg block of ice slides frictionlessly down a plane inclined at 22 $\circ$ a distance of 2 m.What is the normal force on the block of ice?
A)3.0 N
B)18.2 N
C)7.3 N
D)0 N
E)39.2 N

Question

Quizplus · Accepted Answer

The normal force is equal to the component of the gravitational force perpendicular to the plane, which is:$$N = mg\cos	heta = (2 	ext{ kg})(9.8 	ext{ m/s}^2)\cos 22.5^\circ = 18.2 	ext{ N}$$

A 2-Kg Block of Ice Slides Frictionlessly Down a Plane ∘\circ∘

A 2-Kg Block of Ice Slides Frictionlessly Down a Plane $\circ$