A 100-kg object moves on a level surface with a coefficient of friction of 0.40.If the initial velocity is 15 m/s,how far will it travel before coming to rest?
A)25 m
B)29 m
C)15 m
D)11 m

Question

Quizplus · Accepted Answer

We can use the formula for the distance traveled before coming to rest:
d = (v^2)/(2μg)

where d is the distance traveled, v is the initial velocity, μ is the coefficient of friction, and g is acceleration due to gravity (9.8 m/s^2).

Plugging in the given values, we get:

d = (15^2)/(2 x 0.40 x 9.8) = 29 m

Therefore, the object will travel 29 m before coming to rest, which is the best choice.

A 100-Kg Object Moves on a Level Surface with a Coefficient